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Two Dimensional Object

?/128=162/? F...

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?/128=162/? Find ?

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Q. What should come in place x in the equation

\frac{x}{\sqrt{128}} = \frac{\sqrt{162}}{x}

Q. What should come in place of both x in the equation

\frac{x}{\sqrt{128}} = \frac{\sqrt{162}}{x}

.

\sqrt{98} \times \sqrt{162}

\frac{(12)^{6}}{162}

Q. The area of a right isosceles triangle whose hypotenuse is 16

\sqrt{2}

cm is

(a) 125 cm² (b) 158 cm² (c) 128 cm² (d) 144 cm²

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