The correct option is C 255 We know that (n+1)2 n2 = 2n+1 1282 1272 = 2 x 127 + 1 = 254 + 1 = 255 ...

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Standard VIII

Mathematics

Properties of Multiplication of Integers

1282-1272=

Question

128² - 127² =

260

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250

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255

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245

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Solution

The correct option is C
255

We know that (n+1)² - n² = 2n+1

128² - 127² = 2 x 127 + 1 = 254 + 1 = 255

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Similar questions

The square root of $(272^{2} - 128^{2})$ is :

Q. Factorize using middle term splitting method
8 n square+ 10 n - 1272

Subtract the sum of $- 1250$ and $1138$ from the sum of $1136$ and $- 1272.$

Q. Find the value of:
(i) (82)² − (18)²
(ii) (128)² − (72)²
(iii) 197 × 203
(iv)

\frac{198 \times 198 - 102 \times 102}{96}

(v) (14.7 × 15.3)
(vi) (8.63)² − (1.37)²

Find the values of
(i) $(82)^{2} - (18)^{2}$
(ii) $(128)^{2} - (72)^{2}$
(iii) $197 \times 203$
(iv) $\frac{198 \times 198 - 102 \times 102}{96}$
(v) $(14.7 \times 15.3)$
(vi) $(8.63)^{2} - (1.37)^{2}$

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1282 - 1272 =

The correct option is C 255 We know that (n+1)2 - n2 = 2n+1 1282 - 1272 = 2 x 127 + 1 = 254 + 1 = 255

128² - 127² =

The correct option is C
255

We know that (n+1)² - n² = 2n+1

128² - 127² = 2 x 127 + 1 = 254 + 1 = 255