12 ab -9 a -12-16 b -A- 4 b -3B- 3 a -4C- 3 a-44 b-3D- 3 a-44 b-3

The correct option is C (3a + 4)(4b + 3)12ab + 9a + 12 + 16b = 3a × (4b + 3) + 4 × (3 + 4b) We can observe that (4b + 3) is a common factor. The simplified expr ...

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Byju's Answer

Standard VIII

Mathematics

Method of Common Factors

12 ab +9 a +1...

Question

$12 a b + 9 a + 12 + 16 b =$

(4 b + 3)

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(3 a - 4)

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(3a + 4)(4b + 3)

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(3a + 4)(4b - 3)

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Solution

The correct option is C (3a + 4)(4b + 3)
$12 a b + 9 a + 12 + 16 b = 3 a \times (4 b + 3) + 4 \times (3 + 4 b)$
We can observe that $(4 b + 3)$ is a common factor. The simplified expression becomes:
$(4 b + 3) (3 a + 4)$
where, $4 b + 3$ and $3 a + 4$ are the irreducible factors of the given algebraic expression.

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The factor(s) of 12ab + 9a + 12 + 16b is/are:

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The factors of 12ab + 9a + 12 + 16b are

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12ab+9a+12+16b=

The correct option is C (3a + 4)(4b + 3)12ab+9a+12+16b=3a×(4b+3)+4×(3+4b) We can observe that (4b+3) is a common factor. The simplified expression becomes: (4b+3)(3a+4) where, 4b+3 and 3a+4 are the irreducible factors of the given algebraic expression.

$12 a b + 9 a + 12 + 16 b =$