$12 a b x^{2} - ({9 a}^{2} - {8 b}^{2}) x - 6 a b = 0$

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Solution

$12 a b x^{2} - 9 a^{2} x - 8 b^{2} x - 6 a b = 0$
$3 a x (4 b x - 3 a) + 2 b (4 b x - 3 a) = 0$
$3 a x + 2 b = 04 b x - 3 a = 0$
$x = - \frac{2 b}{3 a} x = \frac{3 a}{4 b}$
Therefore, roots of the equation are $- \frac{2 b}{3 a}, \frac{3 a}{4 b}$

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Similar questions

Q. Solve for

x

12 a b x^{2} - (9 a^{2} - 8 b^{2}) x - 6 a b = 0

{12 a b x}^{2} - ({9 a}^{2} - 8 b^{2}) x - 6 a b = 0

, where

a \neq 0 a n d b \neq 0

Q. Evaluate

12 a b x^{2} - (9 a^{2} - 8 b^{2}) x - 6 a b = 0

, where

a \neq 0

and

b \neq 0

Solve each of the following quadratic equations:
$12 a b x^{2} - (9 a^{2} - 8 b^{2}) x - 6 a b = 0$

Find the roots of each of the following equations, if they exist, by applying the quadratic formula:
$12 a b x^{2} - (9 a^{2} - 8 b^{2}) x - 6 a b = 0, w h e r e a \neq 0 a n d b \neq 0$

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12abx2−(9a2−8b2)x−6ab=0

12abx2−9a2x−8b2x−6ab=03ax(4bx−3a)+2b(4bx−3a)=03ax+2b=04bx−3a=0x=−2b3ax=3a4bTherefore, roots of the equation are −2b3a,3a4b

$12 a b x^{2} - ({9 a}^{2} - {8 b}^{2}) x - 6 a b = 0$

$12 a b x^{2} - 9 a^{2} x - 8 b^{2} x - 6 a b = 0$
$3 a x (4 b x - 3 a) + 2 b (4 b x - 3 a) = 0$
$3 a x + 2 b = 04 b x - 3 a = 0$
$x = - \frac{2 b}{3 a} x = \frac{3 a}{4 b}$
Therefore, roots of the equation are $- \frac{2 b}{3 a}, \frac{3 a}{4 b}$