$12 g$ of $M g (a t . m a s s 24)$ on reacting completely with acid gives hydrogen gas, the volume of which at $S T P$ would be:

22.4 L

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11.2 L

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44.8 L

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6.4 L

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Solution

The correct option is C $11.2 L$
$M g + 2 H C l \to M g C l_{2} + H_{2}$

$∵ 24 g M g$ evolves $22.4 L H_{2}$ at $S T P$

$∴ 12 g M g$ evolves $H_{2}$ at $S T P = \frac{22.4}{24} \times 12$

$= 11.2 L$ at $S T P .$

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12g of Mg(at.mass 24) on reacting completely with acid gives hydrogen gas, the volume of which at STP would be:

The correct option is C 11.2LMg+2HCl→MgCl2+H2∵24gMg evolves 22.4LH2 at STP∴12gMg evolves H2 at STP=22.424×12=11.2L at STP.

$12 g$ of $M g (a t . m a s s 24)$ on reacting completely with acid gives hydrogen gas, the volume of which at $S T P$ would be:

The correct option is C $11.2 L$
$M g + 2 H C l \to M g C l_{2} + H_{2}$

$∵ 24 g M g$ evolves $22.4 L H_{2}$ at $S T P$

$∴ 12 g M g$ evolves $H_{2}$ at $S T P = \frac{22.4}{24} \times 12$

$= 11.2 L$ at $S T P .$