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Byju's Answer
Standard XII
Mathematics
Summation of Determinant
∫ 12 loge x d...
Question
∫
1
2
log
e
x
d
x
.
Open in App
Solution
We
have
,
I
=
∫
1
2
log
e
x
d
x
We
know
that
,
x
=
1
,
when
1
<
x
<
2
∴
I
=
∫
1
2
log
e
1
d
x
I
=
∫
1
2
0
d
x
=
0
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