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Division of a Polynomial by a Polynomial

12xy 9x2 - 16...

Question

$12 x y (9 x^{2} - 16 y^{2}) \div 4 x y (3 x + 4 y)$

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Solution

We have,
$12 x y (9 x^{2} - 16 y^{2}) \div 4 x y (3 x + 4 y)$

$\Rightarrow \frac{12 x y (9 x^{2} - 16 y^{2})}{4 x y (3 x + 4 y)}$

$\Rightarrow \frac{12 x y ((3 x)^{2} - (4 y)^{2})}{4 x y (3 x + 4 y)}$

We know that
$x^{2} - y^{2} = (x + y) (x - y)$

Therefore,
$\Rightarrow \frac{3 ((3 x - 4 y) (3 x + 4 y))}{(3 x + 4 y)}$

$\Rightarrow 3 (3 x - 4 y)$

Hence, this is the answer.

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Similar questions

12 x y (9 x^{2} - 16 y^{2})

\div

4 x y (3 x + 4 y)

Q. Factorise the following:

12 x y (9 x^{2} - 16 y^{2}) \div 4 x y (3 x + 4 y)

Q. Factorise the expressions and divide them as directed.

12 x y (9 x^{2} - 16 y^{2}) \div 4 x y (3 x + 4 y)

Q. Factorise the expressions and divide them as directed.

12 x y (9 x^{2} - 16 y^{2}) + 4 x y (3 x + 4 y)

x y (9 x^{2} - 16 y^{2}) \div 4 x y (3 x + 4 y)

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