13. 2 (2rx 3) 10< 6 (x - 2)

Open in App

Solution

Given, 2( 2x+3 )−10<6( x−2 ).

Solve for x,

2( 2x+3 )−10<6( x−2 ) 4x+6−10<6x−12 4x−4<6x−12 −4+12<6x−4x

Further simplify,

8<2x 4<x

All the real numbers greater than 4 are the solutions of inequality, as x is a real number.

Therefore, solution set is ( 4,∞ ).

Suggest Corrections

Similar questions

x = 2 + 2^{\frac{1}{3}} + 2^{\frac{2}{3}}

x^{3} - 6 x^{2} + 6 x

x = 3 + i

x^{2} - 6 x + 13 = 0

2(2x+3)-10 < 6 (x-2)

x^{2} + 6 x + 13 > 0

2 (2 x + 3) - 10 < 6 (x - 2)

Join BYJU'S Learning Program