$(13.96)^{2} - (15.03)^{2} + (18.09)^{2} - 32.65 = ?$

223

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264

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334

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354

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201

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Solution

The correct option is B 264
Here, the given expression can also be written as
$(14)^{2} - (15)^{2} + (18)^{2} - 32 = ?$
or ?=196-25+324-32
or ? =196+324-225-32
or ? =520-257=263 $\approx$ 264

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Similar questions

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Q. Hydrogen gas is prepared in the laboratory by reacting dilute

H C l

with granulated zinc. Following reaction takes place:

Z n + 2 H C l \to Z n C l_{2} + H_{2}

What would be the volume of hydrogen gas is liberated at STP when 32.65 g of zinc reacts with

H C l

Hydrogen gas is prepared in the laboratory by reacting dilute HCl with granulated zinc. Following reaction takes place

$Z n + 2 H C l \to Z n C l_{2} + H_{2}$

Calculate the volume of hydrogen gas liberated at STP when 32.65 g of zinc reacts with HCl. 1 mol of a gas occupies 22.7 L volume at STP; atomic mass of Zn = 65.3u

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(13.96)2−(15.03)2+(18.09)2−32.65=?

The correct option is B 264Here, the given expression can also be written as (14)2−(15)2+(18)2−32=? or ?=196-25+324-32 or ? =196+324-225-32 or ? =520-257=263≈264

$(13.96)^{2} - (15.03)^{2} + (18.09)^{2} - 32.65 = ?$

The correct option is B 264
Here, the given expression can also be written as
$(14)^{2} - (15)^{2} + (18)^{2} - 32 = ?$
or ?=196-25+324-32
or ? =196+324-225-32
or ? =520-257=263 $\approx$ 264