Question

${}_{13}A{1}^{27}$ is a stable isotope, ${}_{13}A{1}^{29}$ is expected to disintegrate by :

• A. $\beta$-emission
• B. $\alpha$-emission
• C. $\gamma$-emission
• D. positron emission

Answer 1

The correct option is A $\beta$-emission

${}_{13}A{1}^{27}$ is a stable isotope; ${}_{13}A{1}^{29}$ is expected to disintegrate by $\beta$-emission.
${}_{13}A{1}^{29}$ has high neutron to proton ratio.
Beta-emission takes place from the elements above the band of stability where neutron to proton ratio is high.
During Beta-emission, neutron is converted to proton.
${}_0{n}^1+{\to }_1{p}^1{+}_1{\beta }^0$