13 Al 27 is a stable isotope- 13 Al 29 is expected to disintegrate by -A- - emissionB- - - emissionC- Proton emissionD- Position emission

The correct option is B β emission n/p ratio is too large, which decreases by β emission. ...

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Nuclear Stability

13 Al 27 is a...

Question

$13^{A l^{27}}$ is a stable isotope. $13^{A l^{29}}$ is expected to disintegrate by :

$α -$ emission

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$β -$ emission

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Position emission

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Proton emission

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Solution

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Similar questions

_{13}^{27} A l

_{13}^{29} A l

$13^{A l^{27}}$ is a stable isotope. $13^{A l^{29}}$ is expected to disintegrate by :

^{23} N a

_{11}^{24} N a

α

β

\frac{N}{P}

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