13. If (2n)!/3!(2n-3)! and n!/2!(n-2)! are in the ratio 44:3 then n is equal to

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\frac{(2 n)!}{3! (2 n - 3)!}

\frac{n!}{2! (n - 2)!}

44 : 3

n

\frac{(2 n)!}{3! (2 n - 3)!}

\frac{n!}{2! (n - 2)!}

If $\frac{(2 n)!}{3! (2 n - 3)!} a n d \frac{n!}{2! (n - 2)!}$ are in the ratio 44:3, find n.

If $\frac{(2 n)!}{(3!) \times (2 n - 3)!} : \frac{n!}{(2!) \times (n - 2)!} = 44 : 3,$ find the value of n.

F i n d t h e v a l u e o f n i f

\frac{(2 n)!}{3! (2 n - 3)!} : \frac{n!}{2! (n - 2)!} = 44 : 3.

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