Question

QUESTION 2.13

The partial pressure of ethane over a solution containing $6.56\times {10}^{-3}g$ of ethane is 1 bar. If the solution contains $5.00\times {10}^{-2}g$ of ethane, then what shall he the partial pressure of gas?

Answer 1

According to Henry's law
The mass of the gas (m) dissolved in solution $\propto$ Partial pressure (p) (At constant temperature).
$\therefore (6.56\times {10}^{-3}g)\propto 1bar$
$(5.00\times {10}^{-2}g)\propto p$
or $p=\frac{(5.0\times {10}^{-2}g)}{(6.56\times {10}^{-3}g)}\times \left(1bar\right)$
= 7.62 bar