Question

$\frac{1}{3}+x=3$, then x =

(a) $\frac{7}{3}$
(b) $\frac{2}{3}$
(c) $\frac{4}{3}$
(d) $\frac{8}{3}$

Disclaimer: There is a misprint in the question, $\frac{1}{x}$ is written instead of x.

Answer 1

$$\begin{gathered} \frac{1}{3}+x=3 \\ \Rightarrow \frac{1}{3}+x-\frac{1}{3}=3-\frac{1}{3} \\ \Rightarrow x=\frac{3\times 3}{1\times 3}-\frac{1}{3} \\ \Rightarrow x=\frac{9}{3}-\frac{1}{3} \\ \Rightarrow x=\frac{8}{3} \end{gathered}$$

Hence, the correct option is (d).