Question

Solve the equation $13(y-4)-3(y-9)-5(y+4)=0.$

Answer 1

Given $13(y-4)-3(y-9)-5(y+4)=0$
Multiply the number outside the bracket to the inside,
$13y-(13\times 4)-[3y-(3\times 9\left)\right]-5y-(5\times 4)=0$
$13y-52-3y+27-5y-20=0$
take $y$ terms together,
$13y-3y-5y-52+27-20=0$
$5y-45=0$
$5y=45$
$y=\frac{45}{5}$
$\therefore y=9$