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130. the velo...

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130. the velocity time equation of a particle moving in a straight line v=2t-4 when t≤2 secs and v=4-2t when t≥2secs the distance travlled by the particle in the time interval between t=0 to t=4secs is?

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Velocity-time equation of a particle moving in a straight line is v = 2t - 4 for t ≤ 2 s and v = 4-2t for t> 2 s. The distance travelled by the particle in the time interval from t = 0 to t = 4 s is (Here, t is in second and v in m/s)

A particle starts moving rectilinearly at time t = 0 such that its velocity ‘v’ changes with time ‘t’ according to the equation $v = t^{2} - t$ where t is in seconds and v in m/s. Find the time interval for which the particle retards.

Q. A particle is moving in straight line. The velocity v of the particle varies with time t as

v = t^{2} - 4 t

. then the distance traveled by the particle in

t = 0

t = 6 s

(where $t$ in second and v is in m/s )

Q. A particle starts moving rectilinearly at time

t = 0

such that its velocity

v

changes with time

t

according to the equation

v = t^{2} - t

t

is in seconds and

v

m s^{- 1}

. The time interval for which the particle retards (i.e., magnitude of velocity decreases) is:

Q. The displacement - time graph of a particle moving along a straight line is given below. Find average velocity between

t = 2 s e c

t = 4 s e c

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