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Question

135 is a natural number whose "digit product" is 1×3×5=15. How many such three digit numbers are possible with digit product 24?

A
4
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B
18
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C
21
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D
16
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Solution

The correct option is A 21
21 three digit numbers possible.
138, 183, 318, 381, 813, 831,
146, 164, 416, 461, 614, 641,
226, 262, 622,234, 243, 324, 342, 432, 423

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