Question

138 gm of $N_2{O}_4$(g) is placed in 3.2 L container at 300 K. The equilibrium vapour density of mixture was found to 30.67. Then (R = 0.082 L atm mol${}^{-1}$K${}^{-1}$)

• A. $\alpha =$ degree of dissociation $N_2{O}_4=0.25$
• B. $K_P$ of $N_2{O}_4\rightleftharpoons 2N{O}_2\left(g\right)$ will be $9$ atm.
• C. Total pressure at equilibrium = $6.75$ atm
• D. The density of equilibrium mixture will be $16.83$ gm/litre.

Answer 1

Answer: (B), (C), (D)

The correct options are
B $K_P$ of $N_2{O}_4\rightleftharpoons 2N{O}_2\left(g\right)$ will be $9$ atm.
C Total pressure at equilibrium = $6.75$ atm
D The density of equilibrium mixture will be $16.83$ gm/litre.