Question

$13824$ is a perfect cube?

• A. True
• B. False

Answer 1

The correct option is A True

Prime factorising $13824$, we get,

$13824=2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\times 2\times 3\times 3\times 3$

$=2^9\times 3^3$.

We know, a perfect cube has multiples of $3$ as powers of prime factors.

Here, number of $2$'s is $9$ and number of $3$'s is $3$, which are the multiples of $3$.

Therefore, $13824$ is a perfect cube.

Hence, the statement is true and option $A$ is true.