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Standard XII

Chemistry

Types of Redox Reactions

14.3g of Na...

Question

$14.3$ g of $N a_{2} C O_{3} . x H_{2} O$ completely neutralises $100$ ml of $1 N H_{2} S O_{4}$ solutions, Value of x is

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Solution

Given that $14.3 g m$ of $N a_{2} C O_{3} . X . H_{2} O$ neutralises $100 m l$ of $1 N H_{2} S O_{4}$ .
If $X = 10$
Then only $14.3 g m$ of $N a_{2} C o_{3} . X . H_{2} O$ neutralises $100 m l$ of $1 N H_{2} S O_{4}$ .

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Similar questions

10

mL of

0.1

H_{2} S O_{4}

is needed for complete the reaction with

25

mL of

11.44

g/L

N a_{2} C O_{3} . x H_{2} O

. The value of

x

is:

0.106

g of

N a_{2} C O_{3}

completely neutralises

40.0

mL of

H_{2} S O_{4}

. Hence, normality of

H_{2} S O_{4}

solution is (write

0.06

6

in the answer) :

Q. 0.7 gm of

n A_{2} C O_{3} . x H_{2} O

is dissolved in 100 ml, 20 ml of which required 19.8 ml of 0.1 N HCl. The value of x is :

0.7 g of Na₂Co₃.XH₂O were dissolved in water and the volume was made to 100mL , 20 mL of this solution required 19.8 mL of N/10 HCl for complete neutralisation, the value of 'x' is

A) 7

B) 3

C) 2

D) 5

0.7 g

N a_{2} C O_{3} \cdot x H_{2} O

was dissolved in water and the volume made up to

100 m L, 20 m L

of it required

19.8 m L

\frac{N}{10} H C l

for completing neutralisation. The value of

x

is:

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14.3g of Na2CO3.xH2O completely neutralises 100ml of 1NH2SO4 solutions, Value of x is

Given that 14.3gm of Na2CO3.X.H2O neutralises 100ml of 1NH2SO4 .If X=10Then only 14.3gm of Na2Co3.X.H2O neutralises 100ml of 1NH2SO4 .

$14.3$ g of $N a_{2} C O_{3} . x H_{2} O$ completely neutralises $100$ ml of $1 N H_{2} S O_{4}$ solutions, Value of x is

Given that $14.3 g m$ of $N a_{2} C O_{3} . X . H_{2} O$ neutralises $100 m l$ of $1 N H_{2} S O_{4}$ .
If $X = 10$
Then only $14.3 g m$ of $N a_{2} C o_{3} . X . H_{2} O$ neutralises $100 m l$ of $1 N H_{2} S O_{4}$ .