Question

14 g of $N_2$ contains $3.01\times {10}^{23}$ nitrogen molecules. If true then enter 1, if false enter 0.

Answer 1

Answer: True (1)

Mass of one mole $N_2$ = $1\times molarmass$ = $1\times (2\times 14)$ = $28$ g

Number of molecules in one mole of $N_2$ or $28$ g $N_2$ = Avogadro Number of molecules = $6.023\times {10}^{23}$ molecules

Number of molecules in $14$ g $N_2$ = $\frac{6.023\times {10}^{23}}{2}$ = $3.01\times {10}^{23}$ molecules