14.The motion of a body falling from rest in a resisting medium is described by the equation dv/dt=a–bv, a and b are constants. The velocity at any time t is

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A particle moves according to the equation $\frac{d v}{d t}$ = $α$ - $β$ v , where $α$ and $β$ are constants. Find the velocity as a funtion of time. Assume body starts from rest.

Q. The velocity of a freely falling body in a resisting medium at any time 't' is given by

v = \frac{A}{B [1 - e^{B t}]} .

The dimensions of 'A' are:

Q. The equation of motion of a body falling under gravity is given by

\frac{d v}{d t} = g - \frac{g}{λ^{2}} v^{2}

.The Velocity as a function of time is? given that

v = 0

t = 0

Q. Equation of motion of a body is

\frac{d v}{d t} = 6 - 3 v,

where

v

is the velocity in

m s^{- 1}

and

t

is the time in second. Assuming particle at rest initially. Then,

The motion of a body is described by the equation $\frac{d v (t)}{d t} = 6 - 3 v (t)$ where $v (t)$ is the speed (in $m s^{- 1}$ ) at time t (in s). If the body was at rest at t = 0, the magnitude of the initial acceleration is

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