Question

14. What happens to the force of attraction between two objects when (i) Their mass are
halved? (ii) Distance between them is increased to 4 times its previous value. (iii)
Distance between them as well as each of the mass is increase to 4 times

Answer 1

Dear student

The universal law of gravitation is,

F = G m₁ m₂ /r ²

Where, G is a constant called the universal gravitational constant and is equal to 6.67 × 10^-11 Nm² /kg²

Now,

1. When their masses are halved, say m₁ becomes m₁/2 and m₂ became m₂/2.
The new force is, F = G(m₁/2)(m₂/2)/r² = F/4

2. Again, if the r is increased by 4 times, say it becomes 4r, the new force is, F = G(m₁)(m₂)/(4r)² = F/16

3. if distance and masses both increases by four-times then F = G ( 4m₁) (4m₂) / (4r^{​​​​​​})² = F


Regards