15÷√10+√20+√40-√5-√80

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Solution

SOLUTION:

√5=2.236, √10=3.162

15/(√10+√20+√40-√5-√80)]
=[15/(√10+√(4×5)+√(4×10)-√5-√(16×5)]
=[15/(√10+2√5+2√10-√5-4√5)]
=[15/(3√10-3√5)]
=[5/(√10-√5)]
=[5(√10+√5)]/[(√10-√5)(√10+√5) ]
=[5(√10+√5)]/[(10−5)]
=[5(√10+√5)]/[5]
=(√10+√5)
= 3.162+2.236
=5.398

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Similar questions

\frac{15}{\sqrt{10} + \sqrt{20} + \sqrt{40} - \sqrt{5} - \sqrt{80}}

X	$0 - 5$	$5 - 10$	$10 - 15$	$15 - 20$	$20 - 25$
F	$40$	$80$	$20$	$16$	$20$

\frac{15}{\sqrt{10} + \sqrt{20} + \sqrt{40} - \sqrt{5} - \sqrt{80}}

\frac{15}{\sqrt{10} + \sqrt{20} + \sqrt{40} - \sqrt{5} - \sqrt{80}}

Evaluate $\frac{15}{\sqrt{10} + \sqrt{20} + \sqrt{40} - \sqrt{5} - \sqrt{80}}$ , it us given that $\sqrt{5} = 2.236$ and $\sqrt{10} = 3.162$

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