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Question

152+202+252+...+1002=

A
71220
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B
71625
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C
71750
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D
71800
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Solution

The correct option is B 71625
S=152+202+252+...+1002 =52(32+42+52+...+202)
Now, 32+42+52+...+202=(12+22+32+42+52+...+202)(12+22)=[20(20+1)(2(20)+1)6]5=1722065=2865

S=25×2865=71625

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