Question

# $\left[15\left(2-y\right)-5\left(y+6\right)\right]=10\left(1-3y\right)$ $,$Solve for $y.$

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Solution

## The given algebraic equation is $\left[15\left(2-y\right)-5\left(y+6\right)\right]=10\left(1-3y\right)$$15\left(2-y\right)-5\left(y+6\right)=10\left(1-3y\right)$$30-15y-5y-30=10-30y$$-15y-5y+30y=10-30+30$$10y=10$$y=\frac{10}{10}$$y=1$Hence$,$ the value of $y$ is $1$

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