15(2x-3)^3-10(2x-3)

Open in App

Solution

15(2x-3)^3-10(2x-3)
Take out 5(2x-3) as a commmon factor
We get 5(2x-3)[3(2x-3)^2-2]
Expanding the square we get 5(2x-3)[3(4x^2-12x+9)-2]
= 5(2x-3)[12x^2-36x+27-2]
= 5(2x-3)(12x^2-36x+25) Answer

Suggest Corrections

Similar questions

\frac{4 x - 3}{2 x + 1} - 10 (\frac{2 x + 1}{4 x - 3}) = 3

(\frac{4 x - 3}{2 x + 1}) - 10 (\frac{2 x + 1}{4 x - 3}) = 3, (x \neq \frac{- 1}{2}, \frac{3}{4})

\frac{4 x - 3}{2 x + 1} - 10 (\frac{2 x + 1}{4 x - 3}) = 3, x \neq \frac{- 1}{2}, \frac{3}{4}

\frac{4 x - 3}{2 x + 1} - 10 (\frac{2 x + 1}{4 x - 3}) = 3; x \neq - \frac{1}{2}, \frac{3}{4}

Solve each of the following quadratic equations:
$(\frac{4 x - 3}{2 x + 1}) - 10 (\frac{2 x + 1}{4 x - 3}) = 3, x \neq \frac{- 1}{2}, \frac{3}{4}$

Join BYJU'S Learning Program