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Importance of Brackets

15-6+6 × 6 ÷9...

Question

15 - (6 + 6 × 6) ÷ (9 + 5) = ?

A

12

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B

24

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C

18

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D

28

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Solution

The correct option is A
12

As we know, the order of operation of BODMAS is as follows:

Brackets

Of

Division

Multiplication

Addition

Subtraction

15 - (6 + 6 × 6) ÷ (9 + 5)

= 15 – (6 + 36) ÷ (9 + 5)

=15 - 42 ÷ 14

=15 - 3

=12

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Similar questions

15 - (6 + 6 × 6) ÷ (9 + 5) = ?

Q. Simplify:
15 - (6 + 6 × 6) ÷ (9 + 5)

Q. Find the value

15 - (6 + 6 \times 6) \div (9 + 5) = ?

(\frac{3}{11} \times \frac{5}{6}) - (\frac{9}{12} \times \frac{4}{3}) + (\frac{5}{13} \times \frac{6}{15})

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

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Importance of Brackets

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