${^{15} C}_{3} + {^{15} C}_{5} + . . . . + {^{15} C}_{15}$ will be equal to

2^{14}

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2^{14} - 15

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2^{14} + 15

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2^{14} - 1

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Solution

The correct option is C $2^{14} - 15$
We know
${^{15} C}_{1} + {^{15} C}_{3} + {^{15} C}_{5} + . . . . . {^{15} C}_{15} = 2^{15 - 1}$
$∴ {^{15} C}_{3} + {^{15} C}_{5} + . . . + {^{15} C}_{15} = 2^{14} - 15$

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Similar questions

The Value of $^{14} C_{2} +^{14} C_{3} +^{14} C_{4} + . . . . . +^{14} C_{14}$ is

^{15} C_{3} +^{15} C_{5} + . . . . . . . +^{15} C_{15}

_{72}^{214} A \to_{- 1}^{0} e

\frac{8}{2^{2} + 1} + \frac{16}{2^{6} + 1} + \frac{32}{2^{14} + 1} + \frac{64}{2^{14} + 1} + \frac{128}{2^{18} + 1} =

\sqrt[4]{21}

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