(15)If tan A and tan B are the roots of x-px+q 0, then the value of sin (A+B) is(a) p /p+q22(b) p/p2+(1-q)22(c) q/p+(1-q)1C)LC

Open in App

Solution

Suggest Corrections

Similar questions

t a n A, t a n B

x^{2} - p x + q = 0

s i n^{2} (A + B)

Given that tan A, tan B are the roots of the equation $x^{2}$ - px + q = 0, then the value of $s i n^{2}$ (A + B) is

tan a, tan b

x^{2} - p x + q = 0

cot a, cot b

x^{2} - r x + s = 0

r s

If tan A, tan B are the roots of $x^{2} - P x + Q = 0$ the value of $s i n^{2}$ (A+B)=(where P, Q $ϵ$ R)

x^{2} - p x - 1 = 0

{sin}^{2} (A + B) = \frac{p^{2}}{1 + p^{2}}

{sin}^{2} (A + B) = \frac{t a n^{2} (A + B)}{1 + t a n^{2} (A + B)}

Join BYJU'S Learning Program