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Question

−15(−x2yz2+2pq2−3mn)=

A
15(x2yz22pq2+3mn)
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B
15(x2yz2+2pq23mn)
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C
15x2yz2+30pq2+45mn
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D
15x2yz230pq245mn
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Solution

The correct option is B 15(x2yz22pq2+3mn)
15(x2yz2+2pq23mn)
=15(x2yz2)15(2pq2)15(3mn)
=15x2yz230pq2+45mn
=15(x2yz22pq2+3mn)

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