15 persons which include A, B and C are to speak at a function. Find the number of ways in which it can be done, if A wants to speak before B and B wants to speak before C.
A
12C3
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B
15C3
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C
15C3×12!
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D
15C3×3!
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Solution
The correct option is C15C3×12! Here, places for A, B and C can be chosen in 15C3 ways. Now, 12 persons remain to speak and these 12 persons can speak in 12! ways. Hence, number of ways in which they can speak is 15C3×12!.