Moles of H2SO4=molarity×volume of solution (in litres)=0.1
Moles of KOH=2×Moles of H2SO4=2×0.1=0.2
Moles of H2O2 used in the first reaction, =Moles of KOH(2×yield of first reaction)=0.22×0.4=0.25
Mole of O2 produced =volume of O2 at STP22.4=6.7222.4=0.3
Moles of H2O2 used in the second reaction,
=Moles of O23×yield of second reaction=0.33×0.5=0.2
Total moles of H2O2=0.25+0.2=0.45
Molarity of H2O2=No. of moles waterVolume of solution in litres=0.450.15=3 M