Question

$150$ students take admission. They are to be put in three sections $A,B,C$ of equal size. The number of ways in which this can be done is

• A. $\frac{150!}{(50!{)}^3}$
• B. $\frac{150!}{(50!{)}^2}$
• C. $\frac{150!}{(50!)}$
• D. None of these

Answer 1

Answer: (A)

$\frac{150!}{(50!{)}^3}$

$150$ students take admission so there are $150!$ possibilities they are divided into $3$ sections of $50$ students each,Therefore,
The number of ways$=\frac{150!}{50!.50!.50!}$
Hence, option 'A' is correct.