150 workers were engaged to finish a piece of work in a certain number of days. Four workers stopped working on the second day, four more workers stopped their work on the third day and so on. It took 8 more days to finish the work. Then the number of days in which the work was completed is
25 days
Suppose the work is completed in n days when the workers stopped working. Since four workers stopped working every day except the first day. Therfore, the total number of workers who worked all the n terms of an A.P. with first term 150 and common difference -4, i.e.,
n2[2×150+(n−1)×−4]=n(152−2n)
Had the workers notstopped working, then the work would have finished in (n-8) days with 150 workers working on each day. Therfore, the total number of workers who would have worked all the n days is 150 (n-8)
∴n(152−2n)=150(n−8)
⇒n2−n−600=0
⇒(n−25)(n+24)=0
⇒n=25
Thus, the work is completed in 25 days.