1500 families with 2 children were selected randomly, and the following data were recorded:

Number of girls in a family

2

1

0

Number of families

475

814

211

Compute the probability of a family, chosen at random, having

(i) 2 girls (ii) 1 girl (iii) No girl

Also check whether the sum of these probabilities is 1.

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Solution

Total number of families = 475 + 814 + 211

= 1500

(i) Number of families having 2 girls = 475

(ii) Number of families having 1 girl = 814

(iii) Number of families having no girl = 211

Therefore, the sum of all these probabilities is 1.

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Similar questions

1500

2

No. of girls in a family	$2$	$1$	$0$
No. of families	$475$	$814$	$211$

2

1

1

\begin{matrix} Number of girls in a family & 2 & 1 & 0 Number of families & 475 & 814 & 211 \end{matrix}

\begin{matrix} N u m b e r o f g i r l s i n a f a m i l y & 2 & 1 & 0 N u m b e r o f f a m i l i e s & 475 & 814 & 211 \end{matrix}

Number of girls in a family	0	1	2
Number of families	211	814	475

1500 families with 2 chidren were selected randomly and the following data were recorded :

\(\begin{array}{|c|c|c|c|}\hline

\text{Number of girls in a family} & 0 & 1 & 2\\\hline

\text{Number of families} & 211 & 814 & 475 \\\hline

\end{array}\)

If a family is chosen at reandam, copute4 the probability that it has :

(i) No girl (ii) I girl (iii) 2 girls (iv) at most one girl (v) more girls then boys [NCERT]

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