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Byju's Answer
Standard XII
Mathematics
nth Term of A.P
15,10,5 , ………...
Question
15
,
10
,
5
,
…
…
…
In this A.P., sum of first 10 terms is
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Solution
15
,
10
,
5
,
.
.
.
…
.
a
=
15
d
=
10
−
15
=
−
5
S
n
=
n
2
[
2
a
+
(
n
−
1
)
d
]
S
10
=
10
2
[
2
×
15
+
(
10
−
1
)
(
−
5
)
]
=
5
[
30
−
5
×
9
]
=
5
[
30
−
45
]
=
5
(
−
15
)
=
−
75
.
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