Question

152 $mL$ of a gas at $STP$ was taken to ${20}^{\circ }C$ and 729 $mm$ pressure. What was the change in volume of the gas? Explain in the value of integer that is x + 10.

Answer 1

Given

$V_1=152mL$

$P_1=1atm=.760mm$

$T_1=273.15K$

$V_2=?$

$P_2=729m$

$T_2={20}^{\circ }C$ or $293.15K$

$V_2=\frac{P_1{V}_1}{T_1}\times \frac{T_2}{P_2}=\frac{760\times 152\times 293.15}{273.15\times 729}=170mL$

$Changeinvolume=V_2-V_1=170-152=18mL$

$x+10=18$

$\therefore x=8$