152 mL of a gas at STP was taken to 20∘C and 729 mm pressure. What was the change in volume of the gas?
A
V2−V1=9mL
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B
V2−V1=18mL
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C
V2−V1=36mL
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D
None of these
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Solution
The correct option is BV2−V1=18mL Given V1=152mL P1=1atm=760mm T1=273.15K V2=? P2=729mm T2=20∘C or 293.15K ∴V2=P1V1T1×T2P2=760×152×293.15273.15×729=170mL ∴Changeinvolume=V2−V1=170−152=18mL