Question

$15Se$ + $SeC{l}_4$ + $4AlC{l}_3$$\to$ $2S{e}_8$[$AlC{l}_4$]${}_2$
Which one of these undergo comproportionation?

• A. Cl
• B. Se
• C. Al
• D. None of these

Answer 1

Answer: (B)

Se

$Se$ undergoes comproportionation it changes from $Se$ to $S{e}^{2+}$ and $S{e}^{4+}$ to $S{e}^{2+}$