$(16)^{- 2}$ when expressed as a power with base 2 equals

2^{- 8}

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2^{- 8}

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2^{- 4}

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2^{4}

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Solution

The correct option is A $2^{- 8}$
Note that $(a^{m})^{n} = a^{m n}$
$⟹ (16)^{- 2} = (4^{2})^{- 3} = ((2^{2})^{2})^{- 2} = (2^{4})^{- 2} = (2)^{- 8}$

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