16, 25, 36, 72, 144, 196, 225

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196

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225

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Solution

The correct option is B 72
Each of the numbers except 72 is a perfect square.

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Similar questions

X

X

(121 - 196), (144 - 225), (36 - 83), (16 - 49)

16 cos 144^{0} . cos 108^{0} . cos 72^{0} . cos 36^{0} =

$s i n 36^{\circ} s i n 72^{\circ} s i n 108^{\circ} s i n 144^{\circ} = \frac{5}{16}$

sin 36^{o} sin 72^{o} . sin 108^{o} . sin 144^{o} = \frac{5}{16}

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