16.8 g of metal carbonate on thermal decomposition gave 8 g of metallic oxide and 8.8 g of carbon dioxide. They follow:

Law of constant proportion

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Law of multiple proportion

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Law of conservation of mass

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None of the above

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Solution

The correct option is C Law of conservation of mass
$M e t a l c a r b o n a t e (16.8 g) \to M e t a l l i c o x i d e (8 g) + C a r b o n d i o x i d e (8.8 g)$

The total mass of reactants (metal carbonate) is 16.8 g.
The total mass of products (metallic oxide + carbon dioxide) is 8 + 8.8 = 16 g.

Since the total mass of reactants and products remains the same, this reaction follows the law of conservation of mass.

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