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Division of Negative Numbers

Question 20 -...

Question

Question 20

$- 16 \div 4$ is not same as

(a) $(- 4) \div 16$
(b) $- (16 \div 4)$
(c) $16 \div (- 4)$
(d) -4

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Solution

$(- 16) \div 4 = - (16 \div 4) = 16 \div (- 4) = \frac{16}{- 4} = - 4$
But division is not commutative, hence
$- 16 \div 4 \neq (- 4) \div 16$ .

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Question 17

$(- 25) \times [6 + 4]$ is not same as

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Question 2

$3 \frac{3}{4} \div \frac{3}{4}$ is equal to

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(d) $\frac{45}{16}$

Q. The cube of the number p is 16 times the number. Find p where, p

\neq

\neq

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Division of Negative Numbers

Standard VIII Mathematics

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