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Question

16g of a radioisotope reduces to one gram in one hour. Its half life period in minutes is-


A

15

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B

30

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C

45

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D

60

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Solution

The correct option is A

15


Step 1: Given data and formula are used:

16g of radioisotope reduces to 1g in 1hour.

Formula used:

Kt=2.303logR0R

Step 2: Substitute values in the formula used-

K×60minutes=2.303log161=2.30360log16=0.038×1.2041=0.04621minutes-1

Step 3: Calculate half life period of radioisotope-

t12=0.693kt12=0.6930.04621t12=14.99=15minutes

Final answer:

Hence, option (A) is correct.


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