Question

16 g of oxygen and 3 g of hydrogen are mixed and kept at 760 mm pressure and 0$$. The total volume occupied by the mixture will be nearly
(A) 22.4 litre
(B) 33.6 litres
(C) 448 litres
(D) 44800 ml

Answer 1

The correct option is D.

Given,

$16g$ of oxygen and $3g$ of hydrogen $pressure=760$

So, the mole of oxygen is $\frac{1}{2}as\frac{16}{32}$and the hydrogen is $\frac{3}{2}$

Therefore the total moles are:

$\frac{1}{2}+\frac{3}{2}=2$

Now,

$PV=nRT$

$V=\frac{nRT}{P}$

$\frac{2\times 0.0821\times 273.15}{1}=44800ml$