Question

$16g$ of oxygen and $3g$ of hydrogen are mixed and kept at $760mm$ pressure and $0^{\circ }C$. The total volume occupied by the mixture will be nearly.

• A. $22.4L$
• B. $33.6L$
• C. $44.8L$
• D. $4480mL$

Answer 1

Answer: (C)

$44.8L$

Gas law
Pv = nRT
$n_T=n_{O_2}+n_{H_2}$

$n_{O_2}=\frac{16}{32}=0.5mol$

$n_{H_2}=\frac{3}{2}=1.5mol$

$n_T=0.5+1.5=2$

$V=\frac{2\times 0.0821\times 273}{1}$ (760 mm = 1 atom, T = 273K)

$V=44.8ltr$