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Question

16 g of oxygen has same number of molecules as in 

(a) 16 g of CO                (b) 28 g of N2               (c) 14 g of N2           (d) 1.0 g of H2


Solution

c & d

The number of molecules can be calculated as follows

Number of molecules =MassMolar mass×Avogadro number(NA)

Number of molecules, in 16 g oxygen =1632×NA=NA2

In 16 g of CO =1628×NA=NA1.75

In 28 g of N2=2828×NA=NA

In 14 g of N2=1428×NA=NA2

In 1 g of H2=12×NA=NA2

So, 16 g of O2=14 g of N2=1.0g of H2

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