Question

$16g$ of $S{O}_x$ gas occupies $5.6L$ at $1atm$ and $273K$. The value of $x$ is:

Answer 1

NO. OF MOLES = volume of gas at STP/22.4 (litres)

= 5.6 / 22.4

= 0.25 moles

now,

we also know that -

no. of moles = weight in gram/molecular mass

by above --

0.25 = 16/mole. mass

molecular mass = 16/0.25 = 64

so, now we know that the molecular mass of SO${}_2$ gas is 64.

so, the value of X here is 2.

and the gas is SO${}_2$ (SULPHUR DIOXIDE)