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Octet Rule

16g of sulphu...

Question

$16$ g of sulphur completely reacts with $38$ g of $F_{2}$ to form $S F_{x}$ . The value of $x$ is:
(Atomic mass of $F = 19$ )

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Solution

The correct option is C $4$
$16 g$ of $S$ reacts with $38 g$ of $F_{2}$
The ratio of moles reacted is $\frac{16}{32} : \frac{38}{19}$
$\Rightarrow \frac{1}{2} : 2$
$\Rightarrow 1 : 4$
So one $S$ atom and $4$ atoms forms $S F_{4}$
So, $x = 4$ .

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16g of sulphur completely reacts with 38 g of F2 to form SFx. The value of x is: (Atomic mass of F=19)

The correct option is C 416g of S reacts with 38g of F2The ratio of moles reacted is 1632:3819⇒12:2⇒1:4So one S atom and 4 atoms forms SF4So, x=4 .

$16$ g of sulphur completely reacts with $38$ g of $F_{2}$ to form $S F_{x}$ . The value of $x$ is:
(Atomic mass of $F = 19$ )

The correct option is C $4$
$16 g$ of $S$ reacts with $38 g$ of $F_{2}$
The ratio of moles reacted is $\frac{16}{32} : \frac{38}{19}$
$\Rightarrow \frac{1}{2} : 2$
$\Rightarrow 1 : 4$
So one $S$ atom and $4$ atoms forms $S F_{4}$
So, $x = 4$ .